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xeni455 on 03/12/2025 15:59 Chatgpt: We have two bodies: A starts from the ground: , upwards. B starts from height : , upwards. Take upward as positive, ground at . Motion under gravity : y(t) = y_0 + v_0 t – frac12 g t^2 Body A (from ground) At impact with the ground : 0 = 0 + v_1 t_A – frac12 g t_A^2 Non-zero solution: t_A = frac{2v_1}{g} Body B (from height ) For B at ground: : 0 = h + v_2 t_B – frac12 g t_B^2 We want them to hit the ground at the same time, so . Substitute: 0 = h + v_2 left(frac{2v_1}{g}right) – frac12 gleft(frac{2v_1}{g}right)^2 0 = h + frac{2v_1 v_2}{g} – frac{2v_1^2}{g} Solve for : h = frac{2v_1^2}{g} – frac{2v_1 v_2}{g} = frac{2v_1 (v_1 – v_2)}{g} Insert , , and : h = frac{2 cdot 80 cdot (80-50)}{10} = frac{2 cdot 80 cdot 30}{10} = frac{4800}{10} = 480 text{m} So the required height is: boxed{h approx 480 text{m}} (Using would give about .)
pak-ma-ndryshe on 03/12/2025 15:59 489.8m sipas [chatit](https://chatgpt.com/share/69305e60-fd5c-8003-91c2-16e51013d3b0)
3 commenti
Chatgpt:
We have two bodies:
A starts from the ground: , upwards.
B starts from height : , upwards.
Take upward as positive, ground at .
Motion under gravity :
y(t) = y_0 + v_0 t – frac12 g t^2
Body A (from ground)
At impact with the ground :
0 = 0 + v_1 t_A – frac12 g t_A^2
Non-zero solution:
t_A = frac{2v_1}{g}
Body B (from height )
For B at ground: :
0 = h + v_2 t_B – frac12 g t_B^2
We want them to hit the ground at the same time, so .
Substitute:
0 = h + v_2 left(frac{2v_1}{g}right) – frac12 gleft(frac{2v_1}{g}right)^2
0 = h + frac{2v_1 v_2}{g} – frac{2v_1^2}{g}
Solve for :
h = frac{2v_1^2}{g} – frac{2v_1 v_2}{g}
= frac{2v_1 (v_1 – v_2)}{g}
Insert , , and :
h = frac{2 cdot 80 cdot (80-50)}{10}
= frac{2 cdot 80 cdot 30}{10}
= frac{4800}{10}
= 480 text{m}
So the required height is:
boxed{h approx 480 text{m}}
(Using would give about .)
489.8m sipas [chatit](https://chatgpt.com/share/69305e60-fd5c-8003-91c2-16e51013d3b0)
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